/* origin: FreeBSD /usr/src/lib/msun/src/e_sqrt.c */
/*
 * ====================================================
 * Copyright (C) 1993 by Sun Microsystems, Inc. All rights reserved.
 *
 * Developed at SunSoft, a Sun Microsystems, Inc. business.
 * Permission to use, copy, modify, and distribute this
 * software is freely granted, provided that this notice
 * is preserved.
 * ====================================================
 */
/* sqrt(x)
 * Return correctly rounded sqrt.
 *           ------------------------------------------
 *           |  Use the hardware sqrt if you have one |
 *           ------------------------------------------
 * Method:
 *   Bit by bit method using integer arithmetic. (Slow, but portable)
 *   1. Normalization
 *      Scale x to y in [1,4) with even powers of 2:
 *      find an integer k such that  1 <= (y=x*2^(2k)) < 4, then
 *              sqrt(x) = 2^k * sqrt(y)
 *   2. Bit by bit computation
 *      Let q  = sqrt(y) truncated to i bit after binary point (q = 1),
 *           i                                                   0
 *                                     i+1         2
 *          s  = 2*q , and      y  =  2   * ( y - q  ).         (1)
 *           i      i            i                 i
 *
 *      To compute q    from q , one checks whether
 *                  i+1       i
 *
 *                            -(i+1) 2
 *                      (q + 2      ) <= y.                     (2)
 *                        i
 *                                                            -(i+1)
 *      If (2) is false, then q   = q ; otherwise q   = q  + 2      .
 *                             i+1   i             i+1   i
 *
 *      With some algebric manipulation, it is not difficult to see
 *      that (2) is equivalent to
 *                             -(i+1)
 *                      s  +  2       <= y                      (3)
 *                       i                i
 *
 *      The advantage of (3) is that s  and y  can be computed by
 *                                    i      i
 *      the following recurrence formula:
 *          if (3) is false
 *
 *          s     =  s  ,       y    = y   ;                    (4)
 *           i+1      i          i+1    i
 *
 *          otherwise,
 *                         -i                     -(i+1)
 *          s     =  s  + 2  ,  y    = y  -  s  - 2             (5)
 *           i+1      i          i+1    i     i
 *
 *      One may easily use induction to prove (4) and (5).
 *      Note. Since the left hand side of (3) contain only i+2 bits,
 *            it does not necessary to do a full (53-bit) comparison
 *            in (3).
 *   3. Final rounding
 *      After generating the 53 bits result, we compute one more bit.
 *      Together with the remainder, we can decide whether the
 *      result is exact, bigger than 1/2ulp, or less than 1/2ulp
 *      (it will never equal to 1/2ulp).
 *      The rounding mode can be detected by checking whether
 *      huge + tiny is equal to huge, and whether huge - tiny is
 *      equal to huge for some floating point number "huge" and "tiny".
 *
 * Special cases:
 *      sqrt(+-0) = +-0         ... exact
 *      sqrt(inf) = inf
 *      sqrt(-ve) = NaN         ... with invalid signal
 *      sqrt(NaN) = NaN         ... with invalid signal for signaling NaN
 */

#include "libm.h"

static const double tiny = 1.0e-300;

double sqrt(double x)
{
        double z;
        int32_t sign = (int)0x80000000;
        int32_t ix0,s0,q,m,t,i;
        uint32_t r,t1,s1,ix1,q1;

        EXTRACT_WORDS(ix0, ix1, x);

        /* take care of Inf and NaN */
        if ((ix0&0x7ff00000) == 0x7ff00000) {
                return x*x + x;  /* sqrt(NaN)=NaN, sqrt(+inf)=+inf, sqrt(-inf)=sNaN */
        }
        /* take care of zero */
        if (ix0 <= 0) {
                if (((ix0&~sign)|ix1) == 0)
                        return x;  /* sqrt(+-0) = +-0 */
                if (ix0 < 0)
                        return (x-x)/(x-x);  /* sqrt(-ve) = sNaN */
        }
        /* normalize x */
        m = ix0>>20;
        if (m == 0) {  /* subnormal x */
                while (ix0 == 0) {
                        m -= 21;
                        ix0 |= (ix1>>11);
                        ix1 <<= 21;
                }
                for (i=0; (ix0&0x00100000) == 0; i++)
                        ix0<<=1;
                m -= i - 1;
                ix0 |= ix1>>(32-i);
                ix1 <<= i;
        }
        m -= 1023;    /* unbias exponent */
        ix0 = (ix0&0x000fffff)|0x00100000;
        if (m & 1) {  /* odd m, double x to make it even */
                ix0 += ix0 + ((ix1&sign)>>31);
                ix1 += ix1;
        }
        m >>= 1;      /* m = [m/2] */

        /* generate sqrt(x) bit by bit */
        ix0 += ix0 + ((ix1&sign)>>31);
        ix1 += ix1;
        q = q1 = s0 = s1 = 0;  /* [q,q1] = sqrt(x) */
        r = 0x00200000;        /* r = moving bit from right to left */

        while (r != 0) {
                t = s0 + r;
                if (t <= ix0) {
                        s0   = t + r;
                        ix0 -= t;
                        q   += r;
                }
                ix0 += ix0 + ((ix1&sign)>>31);
                ix1 += ix1;
                r >>= 1;
        }

        r = sign;
        while (r != 0) {
                t1 = s1 + r;
                t  = s0;
                if (t < ix0 || (t == ix0 && t1 <= ix1)) {
                        s1 = t1 + r;
                        if ((t1&sign) == sign && (s1&sign) == 0)
                                s0++;
                        ix0 -= t;
                        if (ix1 < t1)
                                ix0--;
                        ix1 -= t1;
                        q1 += r;
                }
                ix0 += ix0 + ((ix1&sign)>>31);
                ix1 += ix1;
                r >>= 1;
        }

        /* use floating add to find out rounding direction */
        if ((ix0|ix1) != 0) {
                z = 1.0 - tiny; /* raise inexact flag */
                if (z >= 1.0) {
                        z = 1.0 + tiny;
                        if (q1 == (uint32_t)0xffffffff) {
                                q1 = 0;
                                q++;
                        } else if (z > 1.0) {
                                if (q1 == (uint32_t)0xfffffffe)
                                        q++;
                                q1 += 2;
                        } else
                                q1 += q1 & 1;
                }
        }
        ix0 = (q>>1) + 0x3fe00000;
        ix1 = q1>>1;
        if (q&1)
                ix1 |= sign;
        INSERT_WORDS(z, ix0 + ((uint32_t)m << 20), ix1);
        return z;
}